Медведев вышел в финал турнира в Дубае17:59
思路：倒序单调栈。弹出所有 ≤ 当前身高的元素（这些人都能被看到），count 为弹出数量；若栈非空，还能看到栈顶（第一个更高的人），故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。
。关于这个话题，夫子提供了深入分析
That portability is why John Mielke, senior director of apprenticeship at Associated Builders and Contractors, calls the skilled trades one of the fastest paths to entrepreneurship. Experienced electricians often branch out into their own contracting businesses—an outcome that aligns with Gen Z’s growing interest in working for themselves.
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